When is the next leap year after the given year?
by Aiden '24
def next_leap_year(current_year):
final = current_year - current_year % 4
return final + 4| Function Call | Return Value | |||
|---|---|---|---|---|
| next_leap_year(2018) | → | |||
| next_leap_year(2020) | → | |||
| next_leap_year(2055) | → | |||
| next_leap_year(37669) | → | |||
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